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Consider the following distribution of data from a college survey.icted in JEAndroid Usersthey arepercentageom peaksased on telred 18 andiPhone UsersAges 18 - 30Total4056531058Ages 31 – 406875381225Ages 41 - 5010683911459nfidencTotal216015823742-5'e an(Write all answers as a percentage without the % symbol to 1 decimal.) tu tornilleWhat is the probability that someone chosen at random was aged 41 - 50?나200

Consider The Following Distribution Of Data From A College Surveyicted In JEAndroid Usersthey Arepercentageom Peaksased On Telred 18 AndiPhone UsersAges 18 30To class=

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We need to calculate probabilities with the data in the table.

What is the probability that someone chosen at random was aged 41-50?

[tex]\text{prob}=\frac{succes\text{s cases}}{total\text{ cases}}=\frac{1459}{3742}\approx0.39[/tex]

The probability is 39%.

What is the probability that someone chosen at random was an Android user or aged 41-50?

[tex]\begin{gathered} \text{prob}=\frac{success\text{ cases}}{total\text{ cases}}=\frac{1459+2160-1068}{3742} \\ \text{prob}=\frac{2551}{3742}\approx0.682 \end{gathered}[/tex]

The probability is 68.2%.

What is the probability that someone being aged 41-50 and an Android user?

[tex]\text{prob}=\frac{success\text{ cases}}{total\text{ cases}}=\frac{1068}{3742}\approx0.285[/tex]

The probability is 28.5%.

Given a random person was aged 18-30, what is the probability that they were and iPhone user?

[tex]\text{prob}=\frac{success\text{ cases}}{total\text{ cases}}=\frac{653}{1058}=0.617[/tex]

The probability is 61.7 %.

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