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α =46º
1) Let's start by gathering the data:
S = 15 u²
a= 5.5
b= 7.5
Sketcing out:
2) One of the formulas to find out the area of a triangle is:
[tex]S=\frac{ab\cdot\sin (\alpha)}{2}[/tex]Plugging the given data into the formula we have:
[tex]\begin{gathered} 15=\frac{5.5\cdot7.5\sin (\alpha)}{2}\text{ }\times2 \\ 30\text{ =41.25}\cdot\sin (\alpha) \\ \frac{30}{41.25}=\frac{\text{41.25}\cdot\sin (\alpha)}{41.25} \\ 0.72=\sin (\alpha) \end{gathered}[/tex]2.2) Since we want to know the measure of that angle, then let's make use of the arcsine of (0.72)
[tex]\begin{gathered} \alpha=\sin ^{-1}(0.72) \\ \alpha=46.05\approx46 \end{gathered}[/tex]3) Hence, the missing acute angle is α =46º (rounded off to nearest whole number)
