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You pick a card at random. Without putting the first card back, you pick a second card at rando 4 5 6. What is the probability of picking an odd number and then picking an odd number? Simplify your answer and write it as a fraction or whole number.

Sagot :

Given data:

The three numbers on the cards are 4, 5, 6.

The probability of picking an odd number and then picking an odd number is,

[tex]\begin{gathered} P=\frac{1}{3}\times\frac{0}{2} \\ =0 \end{gathered}[/tex]

Thus, the probability of picking an odd number and then picking an odd number is 0.

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