Answered

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in a 45-45-90 triangle, given the hypotenuse 9√2, find the leg of the triangle

Sagot :

Hypothenuse Z= 9√2

then

Z^2 = X^2 + X^2= 2X^2

(9√2)^2 = 2X^2

then

(9√2)/√2= X

cancel √2, then

9 = X

Then now find perimeter

Perimeter P= Z + X + X = 9√2 + 9 + 9 =

P = 9√2 + 18 = 9•(√2 + 2)

Answer is length of triangle= 9√2 + 18

Leg of triangle X= 9

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