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In the following figures, solve for x. Complete parts (a) through (c)

In The Following Figures Solve For X Complete Parts A Through C class=

Sagot :

Explanation:

Part A:

The image is given below as

Concept:

Using the linear pairs theorem, we will have that

[tex]\begin{gathered} z+80^0=180^0 \\ substract\text{ 80 from both sides} \\ z+80-80=180-80 \\ z=100^0 \end{gathered}[/tex]

Also from the image of the question, we can deduce that

[tex]y=55^0(vertical\text{ angles are equal\rparen}[/tex]

Hence,

To calculate the value of x, we will use the sum of angles in a triangle

The sum of angles in a triangle gives

[tex]180^0[/tex]

By substtituting the values, we will have

[tex]\begin{gathered} x+y+z=180^0 \\ y=55^0 \\ z=100^0 \\ x+y+z=180^{0} \\ x+55+100=180^0 \\ x+155=180^0 \\ x=180-155 \\ x=25^0 \end{gathered}[/tex]

Hence,

The final answer for x in part A is

[tex]x=25^0[/tex]

Part B:

From the image in the question we can see that angle segmen makes up a right angle

Hence,

We will have the relation below

[tex]\begin{gathered} 7x+2x=90^0 \\ 9x=90^0 \\ \frac{9x}{9}=\frac{90}{9} \\ x=10^0 \end{gathered}[/tex]

Hence,

The final answer for x in part B is

[tex]x=10^0[/tex]

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