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Sagot :
As per given by the question,
There are given that;
[tex]\frac{y-3}{9}=\frac{4}{5}[/tex]Now,
Solve the given equation for the value of y.
So,
The given equation can be written as,
[tex]\frac{y-3}{9}-\frac{4}{5}=0[/tex]Then,
[tex]\begin{gathered} \frac{5(y-3)-36}{45}=0 \\ 5y-15-36=0 \\ 5y-51=0 \\ 5y=51 \end{gathered}[/tex]So,
[tex]y=\frac{51}{5}[/tex]Hence, the value of y is;
[tex]\frac{51}{5}[/tex]
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