IDNLearn.com helps you find the answers you need quickly and efficiently. Get accurate answers to your questions from our community of experts who are always ready to provide timely and relevant solutions.

Write a sine function that has an amplitude of 5, a midline of 4 and a period of 3/2

Sagot :

Note that in any sine function :

[tex]y=A\sin (B(x+C))+D[/tex]

Amplitude = A

Verical Shift or midline = D

Period = (2π)/B

Horizontal or Phase Shift = C

From the given,

since we dont have any horizontal shift, C = 0.

Amplitude = 5, so A = 5

Midline = 4, so D = 4

and

Period = 3/2, so equating it to (2 π)/B

[tex]\frac{3}{2}=\frac{2\pi}{B}[/tex][tex]B=\frac{4\pi}{3}[/tex]

Now, substituting the values obtained, the sine function will be :

[tex]y=5\sin (\frac{4\pi}{3}x)+4[/tex]

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.