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Sagot :
By definition, you know that two equations are equivalent when they have the same solution. So, solving the first equation you have
[tex]\begin{gathered} \frac{1}{2}x-8=9 \\ \text{ Add 8 }to\text{ both sides of the equation} \\ \frac{1}{2}x-8+8=9+8 \\ \frac{1}{2}x=17 \\ \text{Multiply by 2 }on\text{ both sides of the equation} \\ 2\cdot\frac{1}{2}x=17\cdot2 \\ x=34 \end{gathered}[/tex]Now, solving the second equation you have
[tex]\begin{gathered} x-8=18 \\ \text{ Add 8 to both sides of the equation} \\ x-8+8=18+8 \\ x=26 \end{gathered}[/tex]Since the equations do not have the same solution then these equations are not equivalent.
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