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spherical balloon is inflated with gas at the rate of 800 cubic centimeters per minute.Find the rates of change of the radius when r=30 centimeters and r=85 centimeters.Explain why the rate of change of the radius of the sphere is not constant even though dV/dt is constant.

Spherical Balloon Is Inflated With Gas At The Rate Of 800 Cubic Centimeters Per MinuteFind The Rates Of Change Of The Radius When R30 Centimeters And R85 Centi class=

Sagot :

Answer

Explanation

Given:

A spherical balloon is inflated with gas at the rate of 800 cubic centimeters per minute means

[tex]\frac{dV}{dt}=800\text{ }cm^3\text{/}min[/tex]

(a) The rates of change of the radius when r = 30 centimeters and r = 85 centimeters is calculated as follows:

[tex]\begin{gathered} V=\frac{4}{3}\pi r^3 \\ \\ \frac{dV}{dr}=\frac{4}{3}\times3\pi r^{3-1} \\ \\ \frac{dV}{dr}=4\pi r^2 \\ \\ But\frac{\text{ }dV}{dr}=\frac{dV}{dt}\div\frac{dr}{dt} \end{gathered}[/tex]

So when r = 30, we have

[tex]\begin{gathered} \frac{dV}{dr}=4\pi(30)^2 \\ \\ \frac{dV}{dr}=4\times\pi\times900 \\ \\ \frac{dV}{dr}=3600\pi \\ \\ From\text{ }\frac{dV}{dr}=\frac{dV}{dt}\div\frac{dr}{dt} \\ \\ Putting\text{ }\frac{dV}{dt}=800,\text{ }we\text{ }have \\ \\ 3600\pi=800\div\frac{dr}{dt} \\ \\ \frac{dr}{dt}=\frac{800}{3600\pi}=\frac{800}{3600\times3.14} \\ \\ \frac{dr}{dt}=0.071\text{ }cm\text{/}min \end{gathered}[/tex]

Therefore, the rate of change of the radius when r = 30 is dr/dt = 0.071 cm/min.

For when r = 25 cm, the rate of change is:

[tex][/tex]