Find expert answers and community insights on IDNLearn.com. Join our Q&A platform to receive prompt and accurate responses from knowledgeable professionals in various fields.

spherical balloon is inflated with gas at the rate of 800 cubic centimeters per minute.Find the rates of change of the radius when r=30 centimeters and r=85 centimeters.Explain why the rate of change of the radius of the sphere is not constant even though dV/dt is constant.

Spherical Balloon Is Inflated With Gas At The Rate Of 800 Cubic Centimeters Per MinuteFind The Rates Of Change Of The Radius When R30 Centimeters And R85 Centi class=

Sagot :

Answer

Explanation

Given:

A spherical balloon is inflated with gas at the rate of 800 cubic centimeters per minute means

[tex]\frac{dV}{dt}=800\text{ }cm^3\text{/}min[/tex]

(a) The rates of change of the radius when r = 30 centimeters and r = 85 centimeters is calculated as follows:

[tex]\begin{gathered} V=\frac{4}{3}\pi r^3 \\ \\ \frac{dV}{dr}=\frac{4}{3}\times3\pi r^{3-1} \\ \\ \frac{dV}{dr}=4\pi r^2 \\ \\ But\frac{\text{ }dV}{dr}=\frac{dV}{dt}\div\frac{dr}{dt} \end{gathered}[/tex]

So when r = 30, we have

[tex]\begin{gathered} \frac{dV}{dr}=4\pi(30)^2 \\ \\ \frac{dV}{dr}=4\times\pi\times900 \\ \\ \frac{dV}{dr}=3600\pi \\ \\ From\text{ }\frac{dV}{dr}=\frac{dV}{dt}\div\frac{dr}{dt} \\ \\ Putting\text{ }\frac{dV}{dt}=800,\text{ }we\text{ }have \\ \\ 3600\pi=800\div\frac{dr}{dt} \\ \\ \frac{dr}{dt}=\frac{800}{3600\pi}=\frac{800}{3600\times3.14} \\ \\ \frac{dr}{dt}=0.071\text{ }cm\text{/}min \end{gathered}[/tex]

Therefore, the rate of change of the radius when r = 30 is dr/dt = 0.071 cm/min.

For when r = 25 cm, the rate of change is:

[tex][/tex]

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.