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Sagot :
SOLUTION
We were asked to find how far the screw will fall in 11 seconds.
How far simply means the distance. So we will find the distance using the formula they gave to us.
[tex]\begin{gathered} So\text{ from the formula }\sqrt[]{d}\text{ = t . 2.8, } \\ \sqrt[]{d}\text{ = t }\times\text{2.8, d = distance that we want to find, t = time = 11seconds} \end{gathered}[/tex][tex]\begin{gathered} \sqrt[]{d\text{ }}\text{ = 2.8t, when we multiply t by 2.8 } \\ \text{Now, we will take the square of both sides to remove the }\sqrt[]{\text{ }}\text{ } \\ (\sqrt[]{d})^2=(2.8t)^2 \\ d=(2.8\times11)^2 \\ d=30.8^2 \\ d\text{ = 948.64} \\ d\text{ = 948.6 to the nearest tenth} \end{gathered}[/tex]Therefore, the answer is 948.6 to the nearest tenth
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