Answer:
[tex]\$17.25[/tex]Explanation: We have to find the hourly rate to bowl, provided the following information:
[tex]\begin{gathered} (x_1,y_1)=(2,39) \\ (x_2,y_2)=(3,56.25) \end{gathered}[/tex]Where x is the number of hours and y is the total cost.
[tex]\begin{gathered} y(x)=mx \\ m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{56.25-39}{3-2} \\ m=\frac{56.25-39}{3-2}=\frac{\$17.25}{1hr} \\ m=\frac{\operatorname{\$}\times17.25}{1hr} \\ \therefore\rightarrow \\ y(x)=17.25x \end{gathered}[/tex]Therefore it costs $17.25 for an hour to bowl.