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Question 13Triesremaining: 3Check for UnderstandingPoints out of2.00Write the equation of the line with a slope of 10 that goes through the point(8,-2) in Slope-Intercept and Point-Slope Form.P FlagquestionSlope-Intercept Form:Point-Slope Form:CheckPrevious page

Question 13Triesremaining 3Check For UnderstandingPoints Out Of200Write The Equation Of The Line With A Slope Of 10 That Goes Through The Point82 In SlopeInterc class=

Sagot :

[tex]y=10x-82\rightarrow slope\text{ intercep form}[/tex][tex]y+2=10x-8\rightarrow Point-SlopeForm[/tex]

Explanation

Step 1

Let

passes throught (8,-2)

slope=20

then

a)slope -intercept form

[tex]y-y_1=m(x-x_1)[/tex]

where

[tex]\begin{gathered} (x_1,y_1)\text{ is a point of the line} \\ m\text{ is the slope of the line} \end{gathered}[/tex]

replace

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=10(x-8) \\ y+2=10x-80 \\ \text{subtract 2 in both sides} \\ y+2-2=10x-80-2 \\ y=10x-82\rightarrow slope\text{ intercep form} \end{gathered}[/tex]

Step 2

Now, Point-Slope Form, use the same equation, but don't isolate y

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=10(x-8) \\ y+2=10x-8\rightarrow Point-SlopeForm \end{gathered}[/tex]

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