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Helaine graphed the equation 12x-4y=3 . what was the slope of Helaines line

Sagot :

Answer:

The slope of Helaine's line is 3

Explanations:

Note that:

The slope - Intercept form of the equation of a line is:

y = mx + c

Where m = the slope

c = the intercept

The given equation is:

12x - 4y = 3

Rewrite the above equation in the form y = mx + c

4y = 12x - 3

Divide through by 4

[tex]\begin{gathered} \frac{4y}{4}=\frac{12x}{4}-\frac{3}{4} \\ \\ y\text{ = 3x - }\frac{3}{4} \end{gathered}[/tex]

The slope, m = 3

The intercept, c = -3/4

Therefore, the slope of Helaines line is 3

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