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Find the real zeros of f (x) =45x -5x^3

Sagot :

We will have the following:

[tex]f(x)=45x-5x^3\Rightarrow f(x)=-5x(x^2-9)[/tex][tex]\Rightarrow f(x)=-5x(x-3)(x+3)[/tex]

So, its zeros are x = -3, x = 0 & x = 3.

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