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Solve by using Substitution: 3x-y=13 2x +2y = -10

Sagot :

[tex]\begin{gathered} 3x-y=13 \\ 2x+2y=-10 \\ y=3x-13 \\ \\ 2x+2(3x-13)=-10 \\ 2x+6x-26=-10 \\ 8x-26=-10 \\ 8x=-10+26 \\ 8x=16 \\ x=\frac{16}{8} \\ x=2 \\ \\ 3x-y=13 \\ 3(2)-y=13 \\ 6-y=13 \\ -y=13-6 \\ -y=7 \\ y=-7 \end{gathered}[/tex]

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