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What is the slope of a this perpendicular line 0=-15-7x+3y? Explain?
put it into slope intercept form y=mx+b where m is slope
0=-15-7x+3y subtract 3y from both sides -3y=-7x-15 multiply both sides by -1 3y=7x+15 divide both sdies by 3 y=7/3x+5 slope is 7/3
to find a line perpendicular to it, the slope of the other line, when multiplied by this line, must equal -1, exg 1/2 and -2/1 are perpenicular -1 and 1 are perpendicular
therefor the line perpendicular to it has a slope of -3/7, exg y=-3/7+3
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