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If f(x) = 2x^2 - 5 and g(x) = 2x + 1, evaluate f(g(x)) when x = -3

Sagot :

[tex]f(x)=2x^2-5[/tex]

[tex]g(x)=2x+1[/tex]

[tex]f[g(x)]=f(2x+1)=2(2x+1)^2-5[/tex]

when x = -3

[tex]\begin{gathered} \Rightarrow[2(2\times-3+1)^2]-5 \\ 2[-5]^2-5=45 \end{gathered}[/tex]

The final answer is 45

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