Answered

Discover new perspectives and gain insights with IDNLearn.com's diverse answers. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.

A concave mirror of focal length 10 cm forms an upright and diminished image of a real object placed at a distance of 5 cm from the mirror. Is this true or false?

Sagot :

Given,

The focal length of the concave mirror, f=10 cm

The object distance, o=5 cm

From the mirror formula, we have,

[tex]\frac{1}{f}=\frac{1}{o}+\frac{1}{i}[/tex]

Where i is the image distance.

On substituting the known formula,

[tex]\begin{gathered} \frac{1}{10}=\frac{1}{5}+\frac{1}{i} \\ \Rightarrow\frac{1}{i}=\frac{1}{10}-\frac{1}{5} \\ =-\frac{1}{10} \\ \Rightarrow i=-10\text{ cm} \end{gathered}[/tex]

And the magnification is given by,

[tex]m=\frac{-i}{o}[/tex]

On substituting the known values,

[tex]\begin{gathered} m=\frac{-(-10)}{5} \\ =2 \end{gathered}[/tex]

Thus the object is not diminished, it is magnified.

Thus the given statement is false.

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.