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factor the equation 3x^2 +16x-12

Sagot :

(3x - 2)(x + 6)

Explanation:

3x² +16x-12​

a = 3, b = 16, c = - 12

a(c) = 3(-12) = -36

The factors of -36 whose sum will give +16 are -2 and 18

3x² + 18x - 2x - 12

3x(x + 6) -2(x + 6)

(3x - 2)(x + 6)

The factorisation: (3x - 2)(x + 6)

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