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length of arc PQ = 3.14 meters (option B)
Explanation:[tex]\begin{gathered} \text{Length of an arc in radians = r}\theta \\ \end{gathered}[/tex]The angle given is in degrees:
[tex]\text{length of an arc using angle in degr}ees\text{ = }\theta/360\times2\pi r[/tex][tex]\begin{gathered} \theta\text{ = 60}\degree \\ PR\text{ = radius =3m } \\ \text{let }\pi\text{ = 3.14} \\ \text{length of arc PQ = }\frac{60}{360}\times2\times3.14\times3 \end{gathered}[/tex][tex]\begin{gathered} \text{length of arc PQ = }\frac{1}{6}\times3.14\times6\text{ = 3.14} \\ \text{length of arc PQ = 3.14 meters ( option B)} \end{gathered}[/tex]