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Sagot :
1) Concentration of Na+
1.1- List the known quantities.
Molarity: 0.304 M Na2SO4.
Volume: 15.0 mL
M= mol/L
1.2- Set the equation
The ion-molecule ratio is 2 Na atoms: 1 molecule Na2SO4.
[tex]M_{Na^+}=0.304\text{ }\frac{mol\text{ }Na_2SO_4}{L}*\frac{2\text{ }mol\text{ }Na^+}{1\text{ }mol\text{ }Na_2SO_4}=0.608\frac{mol\text{ }Na^+}{L}[/tex]The concentration of Na+ is 0.608 M.
2) Concentration of SO4 (2-)
2.1- List the known quantities.
Molarity: 0.304 M Na2SO4.
Volume: 15.0 mL
M= mol/L
2.2- Set the equation
The ion-molecule ratio is 1 SO4 (2-): 1 molecule Na2SO4.
[tex]M_{SO_4^{2-}}=0.304\text{ }\frac{mol\text{ }Na_2SO_4}{L}*\frac{1\text{ }mol\text{ }SO_4^{2-}}{1\text{ }mol\text{ }Na_2SO_4}=0.304\frac{mol\text{ SO}_4^{2-}}{L}[/tex]The concentration of SO4 (2-) is 0.304 M.
3) Concentration of K+
3.1- List the known quantities.
Molarity: 0.200 M KCl.
Volume: 34.6 mL
M= mol/L
3.2- Set the equation
The ion-molecule ratio is 1 K+: 1 molecule KCl.
[tex]M_{K^+}=0.200\frac{mol\text{ }KCl}{L}*\frac{1\text{ }mol\text{ }K^+}{1\text{ }mol\text{ }KCl}=0.200\text{ }\frac{mol\text{ }K^+}{L}\text{ }[/tex]The concentration of K+ is 0.200 M.
4) Concentration of Cl-
4.1- List the known quantities.
Molarity: 0.200 M KCl.
Volume: 34.6 mL
M= mol/L
4.2- Set the equation
The ion-molecule ratio is 1 Cl-: 1 molecule KCl.
[tex]M_{Cl^-}=0.200\frac{mol\text{ }KCl}{L}*\frac{1\text{ }mol\text{ }Cl^-}{1\text{ }mol\text{ }KCl}=0.200\text{ }\frac{mol\text{ }Cl^-}{L}[/tex]The concentration of Cl- is 0.200 M.
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