IDNLearn.com offers a seamless experience for finding and sharing knowledge. Our platform is designed to provide accurate and comprehensive answers to any questions you may have.

The remains of an ancient ball court include a rectangular playing alley with a perimeter of about 18m. The length of the alley is two times the width. Find the length and the width of the playing alley.The width is ? m and the length is ? m.

Sagot :

Given:

Perimeter = 18 m

The formula for the perimeter of a rectangle is:

[tex]P=2l+2w[/tex]

Where:

l = lenght

w = width

In this case, we have that:

l = 2w

Therefore, we substitute the values in the formula:

[tex]\begin{gathered} P=2l+2w \\ 18=2(2w)+2w \end{gathered}[/tex]

And solve for w:

[tex]\begin{gathered} 18=4w+2w \\ 18=6w \\ \frac{18}{6}=\frac{6w}{6} \\ w=3 \end{gathered}[/tex]

For the length:

[tex]l=2w=2(3)=6[/tex]

Answer:

The width is 3 m

The length is 6 m