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state the equation of the axis of symmetry of the function f(x) = 3x^2 + 6x - 2

Sagot :

The given function is:

[tex]f(x)=3x^2+6x-2[/tex]

Complete the square and factor as follows:

[tex]\begin{gathered} f(x)=3(x^2+2x+1)-2-3 \\ f(x)=3(x+1)^2-5_{} \end{gathered}[/tex]

Compare with:

[tex]f(x)=a(x-h)^2+k[/tex]

To get:

[tex](h,k)=(-1,-5)[/tex]

Since the parabola is vertical the axis of symmtery is vertical which is x=-1.

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