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The question and the Triangle is in the same image. I'm on point 3

The Question And The Triangle Is In The Same Image Im On Point 3 class=

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ANSWER

• Ratio: 2

,

• Lengths of the sides of the new triangle: 6, 6√2

,

• Circles: ,see explanation

,

• Triangle: ,see explanation

EXPLANATION

• The ratio is the quotient between the length of segment DE and, for example, segment AB,

[tex]\frac{DE}{AB}=\frac{6}{3}=2[/tex]

• Now, we have to multiply each side of triangle ABC by 2 to obtain the lengths of the sides of triangle DEF,

[tex]\begin{cases}DF=2BC=2\cdot3=6 \\ \\ EF=2AC=2\cdot\sqrt[]{3^2+3^2}=2\cdot\sqrt[]{2\cdot9}=6\sqrt[]{2}\end{cases}[/tex]

• Next, draw the two circles mentioned,

• The intersection between the two circles is point F. The ,triangle is,

View image LejonJ136636
View image LejonJ136636
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