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5/3x+1/3x=13 1/3 + 8/3

Sagot :

[tex]\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x[/tex]

Is this correct?

Now we will add the terms of the left side

[tex]\begin{gathered} \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x \\ \frac{6}{3}x=13\frac{1}{3}+\frac{8}{3}x \end{gathered}[/tex]

Now subtract 8/3 x from both sides

[tex]\frac{6}{3}x-\frac{8}{3}x=\frac{40}{3}+\frac{8}{3}x-\frac{8}{3}x[/tex][tex]-\frac{2}{3}x=\frac{40}{3}[/tex]

Cancel the denominator 3 from both sides

-2x = 40

Divide two sides by -2

[tex]\frac{-2x}{-2}=\frac{40}{-2}[/tex]

x = -20

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