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Explanation:
Total tickets = 500
Tickets number bought by David = 5, 6, 7 and 8
Number of tickets bought by David = 4
Remaining ticket = 500 - Number of tickets bought by David
Remaining ticket = 500 - 4
Remaining ticket = 496
Odds in favour of an event = success for the event/ failures for the event
success for winning the raffle = Number of tickets bought by David = 4
failures for winning the raffle = Remaining ticket = 496
[tex]\begin{gathered} \text{odds in favour of David winning = }\frac{4}{496} \\ \text{odds in favour of David winning = }\frac{1}{124} \\ \\ \text{odds in favour of David winning = }1\text{ : 124 (option C)} \end{gathered}[/tex]