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Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 33.55 N when they are separated by 55.75 cm. What is the magnitude of the charges in microCoulombs ?

Sagot :

Given

Two equal, but oppositely charged particles are attracted to each other electrically.

Force of attraction is F=33.55 N

Distance between them, d=55.75 cm=0.5575 m

To find

What is the magnitude of the charges in microCoulombs ?

Explanation

Let the charge be q.

We know the force of attraction is given by

[tex]\begin{gathered} F=k\frac{q^2}{d^2} \\ \Rightarrow33.55=9\times10^9\times\frac{q^2}{(0.5575)^2} \\ \Rightarrow q=3.39\times(10)^{-5}C \\ \Rightarrow q=\pm33.9\mu C \end{gathered}[/tex]

Conclusion

The charges are:

[tex]+33.9\mu C,-33.9\mu C[/tex]

The magnitude of equal charges are:

[tex]\lvert{q}\rvert=33.9\mu C[/tex]

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