From health tips to tech hacks, find it all on IDNLearn.com. Get thorough and trustworthy answers to your queries from our extensive network of knowledgeable professionals.
Sagot :
First, we write our reaction:
We call solubility to "S"
LaF₃(s) → La³⁺(aq) + 3 F⁻(aq)
Initial - 0.055M (LaCl3) 0
Change +S +3.S
Eq. 0.055+S 3.S
Ksp = 2×10^−19 = [La³⁺]x[F⁻]³ = (0.055+S)x(3.S)³
2×10^−19 = (0.055+S)x(3.S)³ => S = 5.12x10^-7 mol/L x (195.9 g/mol) =>
S = 1.00x10^-4 g/L
(195.9 g/mol = The molar mass of LaF3)
Answer: S = 1.00x10^-4 g/L
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.
