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In a horse race with 6 horses, in a horse race you have 6 horses, you make a bet by predicting the ranking of all 6 horses. If you place your bet at random, whatis the probability that you will get the first and second horse correct and in the correct order?Give your answer as a fraction.

Sagot :

Answer

Probability that one will get the first and second horse correct and in the correct order = ½

Explanation

The probability of an event is given as

[tex]\text{Probability of an event = }\frac{Number\text{ of elements in that event}}{Total\text{ number of elements in the sample space}}[/tex]

For this question, we need to calculate the probability of getting the first and second horse correctly.

Number of elements in the event = Number of predictions with the first and second horse correct in that order = 1 × 1 × 6 × 5 × 4 × 3 = 360

Total number of elements in the sample space = Total number of possible arrangements for the horses = 6 × 5 × 4 × 3 × 2 × 1 = 720

Probability that one will get the first and second horse correct and in the correct order = (360/720) = ½

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