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Find the lowest common multiple of each group. show the factors you used.1) 5,22 and 121

Sagot :

Solution:

Given:

[tex]5,22,121[/tex]

By prime factorization method:

[tex]\begin{gathered} 5=5 \\ 22=2\times11 \\ 121=11\times11 \\ \\ Hence,\text{ the LCM is:} \\ 2\times5\times11\times11 \\ LCM=1210 \end{gathered}[/tex]

Therefore, the LCM is 1,210

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