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Answer:
4x(a+1)(a-2)
Explanation:
Given the polynomial:
[tex]4a^2x-4ax-8x[/tex]First, factor out 4x in all the terms:
[tex]=4x(a^2-a-2)[/tex]Next, factor the expression in the parenthesis:
[tex]\begin{gathered} =4x(a^2-a-2) \\ =4x(a^2-2a+a-2) \\ =4x[a(a-2)+1(a-2)] \\ =4x(a+1)(a-2) \end{gathered}[/tex]The factored form of the polynomial is 4x(a+1)(a-2).