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1. Smoesnail crawls at 3/25 m.p.h. At this rate, how far can he get in 1 2/3 hours?

Sagot :

Answer:

[tex]\frac{1}{5}\text{ miles}[/tex]

Explanation:

Here, we want to get the distance the snail can go in the given time

Mathematically, we have it that:

[tex]\text{Distance = sp}eed\text{ }\times\text{ time}[/tex]

speed = 3/25 mph

Time = 1 2/3 hours = 5/3 hours

Thus, we have it that:

[tex]\text{Distance = }\frac{3}{25}\text{ }\times\frac{5}{3}\text{ = }\frac{1}{5}\text{ miles}[/tex]

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