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Solutions of potassium iodide and lead (II) are mixed. The resulting lead compound is a precipitate.a) substitute symbols and formulas for words b) predict the products. If no reaction occurs, write "NR" after the yields sign. c) include abbreviations for the physical state d) balance the equation

Sagot :

The two compounds that react are:

Potassium iodide: KI

Lead (II):

[tex]Pb^{+2}[/tex]

When the two solutions are mixed the following reaction takes place:

[tex]2KI(aq)+Pb^{+2}(aq)\text{ }\rightarrow2K^{+1}(aq)+PbI_2\text{ (s)}[/tex]

The resulting product is called lead (II) Iodide.

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