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4x^4 - 3x^3 + 2x^2 - 5x +6 divided by (x-2)what is the remainder of this question

Sagot :

Answer:

The remainder is 44

Explanations:

The given polynomial is:

[tex]4x^4-3x^3+2x^2-5x\text{ + 6}[/tex]

The function is to be divided by x - 2

The remainder of the division will be calculated using the remainder theorem

The remainder theorem states that " If a function g(x) is divided by x - a, the remainder of the division will be g(a)"

[tex]\text{Let g(x) = 4x}^4-3x^3+2x^2-5x+6[/tex]

The remainder when g(x) is divided by x -2 is g(2)

[tex]\begin{gathered} g(2)=4(2)^4-3(2)^3+2(2)^2-\text{ 5(2) + 6} \\ g(2)\text{ = 4(16) - 3(8) + 2(4) -5(2) + 6} \\ g(2)\text{ = 64 - 24 + 8 - 10 + 6} \\ g(2)\text{ = 44} \end{gathered}[/tex]