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solve[tex]3 - \frac{x}{2} \geqslant 15[/tex]the equation

Sagot :

GIVEN:

We are given the following inequality;

[tex]3-\frac{x}{2}\ge15[/tex]

Required;

To solve the inequality for x.

Step-by-step solution;

We begin by collecting like terms. Subtract 3 from both sides;

[tex]\begin{gathered} 3-3-\frac{x}{2}\ge15-3 \\ \\ -\frac{x}{2}\ge12 \end{gathered}[/tex]

Now we cross multiply;

[tex]-x\ge24[/tex]

We now multiply both sides of the inequality by -1.

Note that when an inequality is multiplied or divided by a negative value, then the inequality sign flips over.

Therefore;

[tex]\begin{gathered} -x\ge24 \\ \\ -x(-1)\ge24(-1) \\ \\ x\leq-24 \end{gathered}[/tex]

ANSWER:

[tex]x\leq-24[/tex]

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