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Sagot :
To calculate the calories that the water gained, we must use the specific heat of the water. The specific heat of water is 1cal/g°C, which means that it takes one calorie to raise one gram of water 1°C.
Now, we need the mass of water and the temperature difference.
We will calculate the mass of water from its density, the density of water is 1mL/g. Density is defined as:
[tex]Density=\frac{Mass}{Volume}[/tex]We clear the mass and replace the known data:
[tex]Mass=1g/ml\times154.7mL=154.7g[/tex]Now, the temperature difference will be:
[tex]\begin{gathered} \Delta T=T_2-T_1 \\ \Delta T=24.1\degree C-16.3\degree C=7.8\degree C \end{gathered}[/tex]Calories gained by water are calculated from the following equation:
[tex]Q=mCp\Delta T[/tex]where,
Q is the heat or energy that the substance absorbs or releases. In this case, the water will absorb energy.
m is the mass of water = 154.7g
Cp is the specific heat of water, 1cal/g°C
dT is the difference of temperature, 7.8°C
Now, we replace the known data:
[tex]\begin{gathered} Q=154.7g\times1\frac{cal}{g.\degree C}\times7.8\degree C \\ Q=1206.7cal \end{gathered}[/tex]Answer: The water gained 1206.7 calories of heat
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