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hi. This is an equation on some math homework and im not sure how to do it. Could you help?Write an equation of the line that is parallel to y=16 and passes through point (−7,43)

Sagot :

From the given equation y=16, it implies that the line has no slope.

Hence, the slope is zero (0).

From the given point:

[tex]\begin{gathered} (-7,43) \\ x_1=-7,y_1=43 \end{gathered}[/tex]

The equation of the line is given by the equation:

[tex]m=\frac{y-y_1}{x-x_1}[/tex][tex]\begin{gathered} 0=\frac{y-43}{x-(-7)} \\ 0=\frac{y-43}{x+7} \\ \text{cross}-\text{multiply} \\ y-43=0 \\ y=43 \end{gathered}[/tex]

Hence, the equation of the line is y=43

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