1) Given the altitude BD, let's find its measure using some trigonometric relations on the Right Triangle:
1.2) Pythagorean Theorem to find the other leg
b²=a²+c² The hypotenuse, in this case, is labeled as "b"
32²=16²+a²
1024=256+a²
1024-256=a²
768=a²
√768=√c²
a=16√3
2) Now, let's use one trigonometric relation on the Right Triangle, based on the similarity of the triangles:
ah=bc Adjusting it:
bh=ac
32h=16√3*16
32h=256√3
h=256√3/32
h=8√3 ≈ 13.85 ≈13.9
3) So the altitude BC of that triangle is approximately 13.9
