Answered

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By what factors could each equation be multiplied in order to solve the system by linear combination? 2x-3y=8 and 5x+4y=-3A. First equation by 2: second equation by 5 B. First equation by 3; second equation by 4 C. First equation by 3: second equation by 8 D. First equation by 4: second equation by 3

Sagot :

we have these equations

[tex]\begin{gathered} 2x-3y=8 \\ 5x+4y=-3 \end{gathered}[/tex]

In order to solve this system for the x variable, we can multiply the first equation by 4 and the second by 3

This correspond to answer D.

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