Answered

Find accurate and reliable answers to your questions on IDNLearn.com. Ask any question and receive timely, accurate responses from our dedicated community of experts.

A sample of silver at 10°C is heated to 90°C when 1 kcal of heat is added. What is the mass of the silver?

Sagot :

We can use the following formula:

[tex]q=m\cdot c\cdot(T2-T1)[/tex]

Where:

q = heat = 1 kcal = 4184000J

c = specific heat (of silver) = 0.235 J °C /g

m = mass

T1 = Initial temperature = 10°C

T2 = Final temperature = 90°C

Therefore, solve for m:

[tex]\begin{gathered} m=\frac{q}{c(T2-T1)} \\ m=\frac{4184000}{0.235(90-10)} \\ m=222553.1915g \end{gathered}[/tex]

Answer:

222553.1915g

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.