Answered

Connect with knowledgeable individuals and get your questions answered on IDNLearn.com. Our experts provide timely and precise responses to help you understand and solve any issue you face.

A sample of silver at 10°C is heated to 90°C when 1 kcal of heat is added. What is the mass of the silver?

Sagot :

We can use the following formula:

[tex]q=m\cdot c\cdot(T2-T1)[/tex]

Where:

q = heat = 1 kcal = 4184000J

c = specific heat (of silver) = 0.235 J °C /g

m = mass

T1 = Initial temperature = 10°C

T2 = Final temperature = 90°C

Therefore, solve for m:

[tex]\begin{gathered} m=\frac{q}{c(T2-T1)} \\ m=\frac{4184000}{0.235(90-10)} \\ m=222553.1915g \end{gathered}[/tex]

Answer:

222553.1915g

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.