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write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation.(0,0); y=-7x + 5y =

Sagot :

Slope intercept form:

y= mx+ b

Where:

m= slope

b= y-intercept

For: y=-7x+5

m= -7

Perpendicular lines have negative inverse slopes.

Negative inverse of -7 = 1/7

So far we have

y= 1/7x + b

Replace (x,y) fo the given point (0,0) and solve for b:

0= 1/7(0) + b

b= 0

Final equation:

y= 1/7x

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