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We will have the following:
We know that:
[tex]F_c=\frac{mv^2}{r}[/tex]If we double the radius, then:
[tex]F_c=\frac{mv^2}{(2r)}\Rightarrow F_c=\frac{1}{2}\frac{mv^2}{r}[/tex]So, the centripetal force will be half of its original value. [Option A]