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t (x) = 1/x + 3
t (x) ⇒ y
y = 1/x + 3
when x = 1
y = 1/1 + 3 = 1 + 3 = 4
y = 4(Graph 4)
t (x)= -1/x + 3
t (x) ⇒ y
y = -1/x + 3
when x = 1
y =-1/1 + 3 = - 1 + 3 = 2
y = 2(Graph 2 )
Hence, the correct graph to these equations is Graph 4 & Graph 2