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Please help me!A boy on a skateboard travels the first 600m of a trip at an average speed of 2 m/s. He then travels the next 800m in 200s and spends the last 100s at a speed of 5 m/s. Find the average speed of the bicyclist for this trip.

Sagot :

average speed = total distance / total time

speed x time = distance

part 1

D1= 600 m, s1=2m/s

Part 2

d2=800m, t2=200s

Part 3

s3=5m/s ,t3=100s

time1 = Distance1/speed1 = 600m/2m/s = 300s

Distance3 = speed3 x time 3 = 5 m/s x 100s = 500m

Total distance = d1+d2+d3 = 600 + 800 + 500 = 1900m

Total time = t1+t2+t3 =300 + 200 + 100 = 600 s

Avg speed = 1900m/600s = 3.17 m/s

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