Answered

Connect with a global community of knowledgeable individuals on IDNLearn.com. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.

In an electrical circuit with resistors placed in parallel, thereciprocal of the total resistance is equal to the sum of thereciprocals of each resistance:

In An Electrical Circuit With Resistors Placed In Parallel Thereciprocal Of The Total Resistance Is Equal To The Sum Of Thereciprocals Of Each Resistance class=

Sagot :

Answer:

C

[tex]R_2=16.16\Omega[/tex]

Explanation:

Given the below equation;

[tex]\frac{1}{R_c}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]

We're also given;

[tex]\begin{gathered} R_1=25\Omega \\ R_c=10\Omega \end{gathered}[/tex]

Let's substitute the given values into the equation, we'll have;

[tex]\frac{1}{10}=\frac{1}{25}+\frac{1}{R_2}[/tex]

Let's subtract 1/25 from both sides of the equation;

[tex]\begin{gathered} \frac{1}{10}-\frac{1}{25}=\frac{1}{R_2} \\ \frac{5-2}{50}=\frac{1}{R_2} \\ \frac{3}{50}=\frac{1}{R_2} \end{gathered}[/tex]

Let's cross multiply;

[tex]\begin{gathered} 3R_2=50 \\ R_2=\frac{50}{3} \\ R_2=16.16\Omega \end{gathered}[/tex]

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.