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When we have a right angled triangle, it means the triangle has a right angle and two acute angles all equally summing up to 180 degrees.
When we have an isosceles triangle, it means there are two equal acute angles.
Therefore, by combining these two statements, we can get the value of the acute angles. A plot is given below.
[tex]\begin{gathered} 90+x+x=180 \\ 90+2x=180 \\ \text{Subtract 90 from both sides to get:} \\ 2x=90 \\ \text{Divide both sides by 2 to get:} \\ x=45^o \end{gathered}[/tex]Next step is to get Tan A.
We can use trigonometric ratios and Pythagoras theorem to get:
[tex]\begin{gathered} AB^{}=\sqrt[]{AC^2+BC^2} \\ AB=\sqrt[]{1^2+1^2} \\ AB=\sqrt[]{2} \end{gathered}[/tex]For Tan A, we employ the Soh Cah Toa to get:
[tex]\begin{gathered} \tan A=\frac{\text{opposite}}{\text{adjacent}} \\ \tan A=\frac{1}{1}=1 \end{gathered}[/tex]Therefore, Tan A = 1
