To see the equation we know that the general equation of a line is:
[tex]y=mx+b[/tex]
Where m is the slope. So you know that the slope is 1.2, then you have an equation like this:
[tex]y=1.2x+b[/tex]
Since b is just a number we can say that this is also equal to:
[tex]y=1.2(x+c)[/tex]
We'll write it this way so it's similar to the options.
Then you know that the line pases through point (5,0). To find the value of constant c we replace the value of x and y from this point (x = 5 and y=0):
[tex]0=1.2(5+c)[/tex]
And clear c from this expression
[tex]0=5+c\Rightarrow c=-5[/tex]
So the answer is:
[tex]y-0=1.2(x-5)[/tex]
