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What are the coordinates of point B on AC such that the ratio of AB to BC is 5 : 6

What Are The Coordinates Of Point B On AC Such That The Ratio Of AB To BC Is 5 6 class=

Sagot :

We have a segment AC, with the point B lying between A and C.

The ratio AB to BC is 5:6.

The coordinates for A and C are:

A=(2,-6)

C=(-4,2)

We can calculate the coordinates of B for each axis, using the ratio of 5:6.

[tex]\begin{gathered} \frac{x_a-x_b}{x_b-x_c}=\frac{2-x_b}{x_b+4}=\frac{5}{6}_{} \\ 6\cdot(2-x_b)=5\cdot(x_b+4) \\ 12-6x_b=5x_b+20 \\ -6x_b-5x_b=20-12_{} \\ -11x_b=8 \\ x_b=-\frac{8}{11}\approx-0.72\ldots \end{gathered}[/tex]

We can do the same for the y-coordinates:

[tex]\begin{gathered} \frac{y_a-y_b}{y_b-y_c}=\frac{-6-y_b}{y_b-2}=\frac{5}{6} \\ 6(-6-y_b)=5(y_b-2) \\ -36-6y_b=5y_b-10 \\ -6y_b-5y_b=-10+36 \\ -11y_b=26 \\ y_b=-\frac{26}{11}\approx-2.36\ldots \end{gathered}[/tex]

The coordinates of B are (-8/11, -26/11).

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