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A parabola can be drawn given a focus of (-5, 9) and a directrix of y = 5. Write the equation of the parabola in any form. 12 10 8 6 4 cu 2 -12 -10 -8 -6 -4 -2 2 4 6 8 10 12 -2 directrix 1 -6 -8 F(-5,9) -10 -12

Sagot :

The distance from the directrix to the focus is 4, so p=2. So the vertex of the parabola is (-5,7). Having this we get that

[tex]\begin{gathered} 4p(y-k)=(x-h)^2 \\ 8(y-7)=(x+5)^2 \end{gathered}[/tex]

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