IDNLearn.com is your reliable source for expert answers and community insights. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.

The perimeter of rectangle A is 10 cm and its area is 6 cm2. The perimeter of rectangle B is 20 cm. What is the area of rectangle B assuming these two rectangles are similar?

Sagot :

The perimeter of rectangle A is 10 cm

Perimeter of A = 2x+2y=10 cm, then:

Perimeter of A = 2(x+y)=10

Perimeter of A = x+y=5

We also know that the area of A= xy= 6 cm²

Then, we can admit x=3 and y=2.

Both rectangles are similar.

[tex]\frac{x_a}{y_a_{}}=\frac{x_b}{y_b}[/tex]

[tex]\begin{gathered} \frac{3}{2}=\frac{x_b}{y_b} \\ x_b=\frac{3y_b}{2_{}} \end{gathered}[/tex]

Perimeter of B

[tex]\begin{gathered} 2x_b+2y_b=20 \\ x_b+y_b=10 \\ \frac{3y_b}{2}+y_b=10 \\ 3y_b+2y_b=20 \\ 5y_b=20 \\ y_b=4 \end{gathered}[/tex][tex]\begin{gathered} x_b=\frac{3y_b}{2} \\ x_b=\frac{3\cdot4}{2} \\ x_b=\frac{12}{2} \\ x_b=6 \end{gathered}[/tex]

Therefore

Area of B = 4 x 6 cm² = 24 cm²

View image JhaydenS449701
View image JhaydenS449701