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Sagot :
The perimeter of rectangle A is 10 cm
Perimeter of A = 2x+2y=10 cm, then:
Perimeter of A = 2(x+y)=10
Perimeter of A = x+y=5
We also know that the area of A= xy= 6 cm²
Then, we can admit x=3 and y=2.
Both rectangles are similar.
[tex]\frac{x_a}{y_a_{}}=\frac{x_b}{y_b}[/tex][tex]\begin{gathered} \frac{3}{2}=\frac{x_b}{y_b} \\ x_b=\frac{3y_b}{2_{}} \end{gathered}[/tex]Perimeter of B
[tex]\begin{gathered} 2x_b+2y_b=20 \\ x_b+y_b=10 \\ \frac{3y_b}{2}+y_b=10 \\ 3y_b+2y_b=20 \\ 5y_b=20 \\ y_b=4 \end{gathered}[/tex][tex]\begin{gathered} x_b=\frac{3y_b}{2} \\ x_b=\frac{3\cdot4}{2} \\ x_b=\frac{12}{2} \\ x_b=6 \end{gathered}[/tex]Therefore
Area of B = 4 x 6 cm² = 24 cm²


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